When A = 300, solve the equation
​

Solution given:

a=300

and equation is:

x²-40x+a=0

when a=300

x²-40x+300=0

making it a perfect square

x²-2*20x+20²-20²+300=0

(x+20)²-400+300=0

(x+20)²=100

x+20=±10

taking positive

x+20=10

x=10-20

x=-10

taking negative

x+20=-10

x=-10-20

z=-30

when A=300

x=-10 or -30

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0