(x^2+1)(x-1)=0 help me pls

x = ±i ,  x=1

Step-by-step explanation:

(x^2+1)(x-1)=0

Using the zero product property

x^2 +1 = 0   x-1= 0

x^2 = -1       x=1

Taking the square root of the equation on the left

sqrt(x^2) = sqrt(-1)

x = ±i   where  i is the imaginary number

We still have x=1 from the equation on the right

step-by-step explanation:

$8

step-by-step explanation:

it is pretty much backwards.

you take the 4x2 multiply that, and that is = $8