three different are rung at intervals of 36 minutes 40 minutes and 48 minutes if they were rung together at 9 a. m. at what time would they be rung together again?​

To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.

Prime factorization of 36=2×2×3×3

Prime factorization of 40=2×2×2×5

Prime factorization of 48=2×2×2×2×3

Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.

720seconds=  

60

720

​

minutes=12minutes

Hence, all the bells will ring together after 12 mi

9pm or 12 hours from 9am.

f(x) = y

f(-3) = -5

step-by-step explanation: