A game is played using one die. If the dio is rolled and shows 5, the player wins $35. If the die shows any number other than 5, the player wins nothing a. If there is a charge of $7 to play the game, what is the game's expected value

Let random variable "x" be a count of player gain.

X-values are: 4, -1

P(x=4) = 1/6; P(x= -1) = 5/6

E(x) = (1/6)(4) + (5/6)(-1)

E(x) = [4-5]/6

E(x) = -1/6 = -17 cents

Cheers,

Stan H.

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it