During a 1966 Tabiona High School track meet, Levere ran the 100 yard dash in 10.63 seconds. Ross took second with a time of 10.98 seconds.
a. Levere’s time was % shorter than Ross’.
b. Ross’ time was % longer than Levere’s.
c. Levere’s time was % of Ross’.

a) 3.19

b) 3.29

c) 96.81

Step-by-step explanation:

Question a:

Levere's: 10.63s

Ross: 10.98s

10.98 - 10.63 = 0.35s shorter than 10.98s, so:

0.35*100%/10.98 = 3.19% shorter.

Question b:

35s longer than 10.63s, so:

0.35*100%/10.63 = 3.29% longer.

Question c:

3.19% shorter, so 100 - 3.19 = 96.81% of Ross.

the final function for the graph becomes x-2=-1. before graphing you solve the equation, where x=1. then graph accordingly.   ( on the x-axis, 1 on the line will possess a vertical line.)

step-by-step explanation: