A bag contains 4 purple beads and 3 green beads. A bead is drawn and then replaced before drawing the second bead. Find the probability both beads drawn are green. A) 16/49
B) 6/7
C) 6/49
D) 9/49

9/49

Step-by-step explanation:

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

Replace the bead

4 purple beads and 3 green beads= 7 beads

P( green) = green = total = 3/7

P( green , replace, green) = 3/7 * 3/7 = 9/49

answer: 140

step-by-step explanation:

so just add all then it will be your answer but i am not pretty sur eif it is but hope this i am here to people

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: