State and prove the converse of the pythagorean theorem using a two-column proof

Step-by-step explanation:

I'm from the UK and I'm not familiar with a two column proof, but the following proves the converse.

Draw 2 right angled triangles with the 2 legs = a and b in each case and the longest side = c in one triangle and f in the other.

By Pythagoras a^2 + b^2 = c^2   (Given)

Also in the other triangle a^2 + b^2 = f^2,  if it is right-angled.

Therefore a^2 = f^2 and a = f.

So the 2 triangles are congruent by SSS.

So m < C  in one triangle = m < F  ( the angles opposite the hypotenuse)

Therefore the second triangle is right angled .

This completes the proof.

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form