Calculate the axis of symmetry in the equation Y = (x+1) (x-4) Come on anyone please hel.

Every parabola has a turning point called the axis of symmetry,so for this question you just have to find the turning points

x turning point= -b/2a,and the y turning point is gotten by replacing the value of x in the equation

y=(x+1)(x-4)

=x^2-3x-4

a is 1,b is -3 and c is -4

x= -(-3)/2(1)

=1.5

and y=x^2-3x-4

=1.5^2-3(1.5)-4

= -6.25

therefore the axis of symmetry is (1.5,-6.25)

I hope this helps

the last choice

step-by-step explanation: