What is the equation of the line passing through the points (2, -1) and (5, -10) in slope-intercept form? O y=-3x-5 O y=-3x+5 O Y= 3x-5 O y = 3x + 5​

y= -3x+5

Step-by-step explanation:

firstly find the gradient given by the formula

m=y2-y1/x2-x1

so in this case y2 is -10,x2 is 5,y1 is -1 and x1 is 2

m= -10+1/5-2

m= -9/3

= -3

after finding the gradient use the equation

y-y1=m( x-x1)

y+1= -3(x-2)

y+1= -3x+6

y= -3x+6-1

y= -3x+5

I hope this helps

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)