ou invested 7000 between two accounts paying 4% and 9% annual​ interest, respectively. If the total interest earned for the year was $430 how much was invested at each​ rate? ​$ nothing was invested at and ​$ nothing was invested at

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Step-by-step explanation:

Let x represent the amount invested at 9%. Then 7000-x was invested at 4% and the interest earned was ...

  9%·x +4%(7000-x) = 430

  5%·x +280 = 430 . . . . . . . . . simplify

  0.05x = 150 . . . . . . . . . . . subtract 280

  x = 3000 . . . . . . . . . . divide by 0.05

$3000 was invested at 9%; $4000 was invested at 4%.

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24