What is the largest value of x for which the following equation has a real solution (x, y)?

x = 9/2

Step-by-step explanation:

x^2+7x+y^2+4y=191/4

Complete the square: (x+7/2)^2-(49/4)+(y+2)^2-4 = 191/4

Simplify: (x+7/2)^2+(y+2)^2=191/4+49/4+4

(x+7/2)^2 + (y+2)^2 = 64

(x+7/2)^2 + (y+2)^2 = (8)^2

Center of circle -> (-7/2, -2)

Radius -> 8

-7/2 + 8 = 9/2

x = 9/2

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.