What is the equation of the line that is parallel to the given line and passes through the point (-2, 2)?
(-2, 2)
y = x+4
y= x +
5 -3 -2 -1.
y = -5x + 4
O y= -5x +
+ 13
| (0.3)
(-5,-)

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)