Find f(2) given f(x) = -3x^2 + 2x+11

f(2)=-3(2)^2+2*2+11

f(2)=-3(2)^2+2*2+11 =-3*4+4+11

f(2)=-3(2)^2+2*2+11 =-3*4+4+11 =-12+4+11

f(2)=-3(2)^2+2*2+11 =-3*4+4+11 =-12+4+11 =3

hence, f(2)=3

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°