An old-fashioned Chinese restaurant offers a family dinner where you get to choose one dish from “column A” (which has 8 dishes), one dish from “column B” (which has 10 dishes) and one dish from “column C” (which has 5 dishes). How many different family dinners can be chosen? There are ___ possible dinners.

There are 400 possible dinners.

Step-by-step explanation:

There are 8 dishes to choose from column A. For each of these 8 dishes, there are 10 dishes to pair with. For each of these 10 dishes, there are 5 dishes to go with from column C.

Therefore, multiply to get possible dinners.

*Note: Since the order of which you choose is fixed, we do not need to account for rearrangements of the same three dishes.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

to have more of what you want like money

step-by-step explanation:

save it by not spending on unnecessary stuff and have more