Find the Measure of one interior angle for each polygon

5 corners : 108 degrees

6 corners : 120 degrees

Step-by-step explanation:

there are (at least) 2 different views to get the result :

officially (usually the teachers' preferred method) you consider a polygon as a combination of non-overlapping triangles. a polygon with n corners or edges we can split into n-2 such triangles.

each triangle has an angle sum of 180 degree.

so, the polygon angle sum is (n-2)×180 degrees.

and each (internal) angle is then (n-2)×180/n

n = 5 : (5-2)×180/5 = 3×36 = 108 degrees

n = 6 : (6-2)×180/6 = 4×30 = 120 degrees

the second approach (I prefer) goes after the external angles of the polygon.

the sum of all external angles in any polygon is 360 degrees (a full circle).

for n corners/edges each external angle is 360/n.

and the internal angle is then the complement to 180 degrees = 180 - 360/n

n = 5 : 180 - 360/5 = 180 - 72 = 108 degrees

n = 6 : 180 - 360/6 = 180 - 60 = 120 degrees

step-by-step explanation:

just plug in each number for x and see which ones work and don't