Identify the 42nd term of an arithmetic sequence where a_1=-12 and a_27=66

a₄₂ = 107

Step-by-step explanation:

The nth term of an arithmetic sequence is

= a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Given a₂₇ = 66 , then

a₁ + 26d = 66 , that is

- 12 + 26d = 66 ( add 12 to both sides )

26d = 78 ( divide both sides by 26 )

d = 3

Then

a₄₂ = - 16 + (41 × 3) = - 12 + 123 = 111

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

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step-by-step explanation: