A plane has a takeoff speed of 324km/h and requires 1.35km to reach that speed. Determine the acceleration of the plane and the time required to reach this speed.[4]

If the plane is starting from rest, then the acceleration a that it needs in order to speed up to 324 km/h = 90.0 m/s over a distance of 1.35 km = 1350 m satisfies

(90.0 m/s)² = 2a (1350 m)   ==>   a = 3.00 m/s²

(use the kinematic equation, v ² - v₀² = 2a ∆x)

and the amount of time t needed to reach this speed is such that

90.0 m/s = (3.00 m/s²) t   ==>   t = 30.0 s

(v = v₀ + at )

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a