Tristen is packing lunch boxes for the school trip. Each lunch box consists of 1 sandwich, 1 fruit, and 1 drink. Tristen can choose from 3 types of sandwiches, 4 types of fruit, and 2 types of drinks. How many different lunch boxes can Tristen pack? (question: is this a combination or a permutation?

(please answer legitimately I will give you the brainliest)

Step-by-step explanation:

3*4*2=24

Even if he doesn't use them all, he has 24 choices.

These kind of problems are permutation type problem. Order is not critical. Imagine yourself preparing such a meal. You have choices to be made in Sandwiches, fruits and drinks. It does not matter which order you set up the lunch box. It only matters that you chose.

You can't leave one out, nor does the problem allow you to trade (say) 2 drinks for one fruit.

v v cj van config k tbs eng r.c r.c fcb fb gb frfr

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.