If I needed to write in this format (A U B) how would i write it

n(AUB)=n(A)+n(B)–n(AnB)

n(AUB)=n⁰(A)+n⁰(B)+n(AnB)

Step-by-step explanation:

This is the formula i have learned. Hope this will help u. U can use them according the question type.

the one on the bottom left

step-by-step explanation:

all of the other ones have a specific pattern

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.