AVX Home Entertainment Inc recently began a "no-hassles" return policy. A sample of 505 customers who recently returned items showed 320 thought the policy was fair, 150 thought it took too long to complete the transaction, and the rest had no opinion. On the basis of this information, make an inference about customer reaction to the new policy. (Round your answers to 1 decimal place.) Customer reaction Percent
Fair %
Too long %
No opinion %

Step-by-step explanation:

Given

--- customers

Required

Complete the table

To complete the table, we simply divide each value by the total number of customers.

So, we have:

Express as percentage

Express as percentage

For the last set, the percentage is calculated using:

So, we have:

Collect like terms

i think its doubled. let me know

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.