The length of a rectangular-shaped patio is 3 feet shorter than four times its width. A. Write an equation to represent the area of the patio.
B. If the patio has an area of 370ft square, find the dimensions of the patio

A. A = 4x² – 3x

B. Dimension = 37 ft × 10 ft

Step-by-step explanation:

A. Writing an equation to represent the area of the patio.

From the question given above,

Length (L) = (4x – 3) ft

Width (W) = x ft

Area (A) =?

Area of a rectangle is given by:

Area (A) = Length (L) × Width (W)

A = L × W

A = (4x – 3)x

Clear bracket

A = 4x² – 3x

B. Determination of the dimensions of the patio.

Area (A) = 370 ft²

Dimensions =?

Next, we shall determine the width and length. This can be obtained as follow:

From (A) above,

A = 4x² – 3x (1)

A = 370 (2)

Equating equation 1 and 2, we have

4x² – 3x = 370

Rearrange

4x² – 3x – 370 = 0

Solving by formula method:

4x² – 3x – 370 = 0

Coefficient of x² (a) = 4

Coefficient of x (b) = –3

Constant (c) = –370

x = –b ± √(b² – 4ac) / 2a

x = –(–3) ± √(–3² – (4×4×–370)) / 2×4

x = 3 ± √(9 + 5920) / 8

x = 3 ± √(5929) / 8

x = 3 ± 77 / 8

x = (3 + 77) / 8 or (3 – 77) / 8

x = 80/8 or –74/8

x = 10 or –37/4

Since measurement can not be negative, thus,

x = 10

Width (W) = x ft

x = 10

W = 10 ft

Length (L) = 4x – 3 ft

x = 10 ft

L = 4(10) – 3

L = 40 – 3

L = 37 ft

Finally, we shall determine the dimensions. This is illustrated below:

W = 10 ft

L = 37 ft

Dimension =?

Dimension = L × W

Dimension = 37 ft × 10 ft