dos móviles se encuentran separados 480m ; de pronto parten los dos en forma simultanea al encuentro del otro con rapidez de 20 y 10 m/s, respectivamente . ¿dentro de cuanto tiempo se producirá el encuentro de los móviles ?

4 & 3

step-by-step explanation:

factor of 108=2×2×3×3×3=2×2×3^3=the number is 4 because 2 only occurs 2 times and 2×2=4 and factor of 2187=3^3×3^3×3=the number is 3 because 3 onlyvoccur 1 time.

this is false ^.^ lol

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²