mâ cdf = 43° , mâ gdf = 114°, mâ gde = 23°, mâ edh = 23° , mâ cdh = 157°
step-by-step explanation:
since, it is given that de bisects the angle gdh â de divides the angle gdh into two equal angles.
â mâ gde = mâ edh
â 8¡x - 1 = 6¡x + 5
â x = 3
so, mâ gde = 8¡x - 1 = 23°
and mâ edh = 23°
now, it is given â cde is an straight angle so, mâ cde = 180°
â mâ cdf + mâ fdg + mâ gde = 180°
â 43° + mâ fdg + 23° = 180°
â mâ fdg = 114°
again, mâ cde = mâ cdh + mâ edh = 180°
mâ cdh + 23° = 180°
â mâ cdh = 157°