Find the zeroes of the polynomial and verify the relationship between the zeroes and coefficients 1. 6x^2 - 3 - 7x
2. 3x^2 - x - 4

Step-by-step explanation:

1. Given  f(x) = 6x2 – 7x – 3

To find the zeros

Let us put f(x) = 0

⇒ 6x2 – 7x – 3 = 0

⇒ 6x2 – 9x + 2x – 3 = 0

⇒ 3x(2x – 3) + 1(2x – 3) = 0

⇒ (2x – 3)(3x + 1) = 0

⇒ 2x – 3 = 0 Or 3x + 1 = 0

x = 3/2                      x = -1/3

It gives us 2 zeros, for x = 3/2 and x = -1/3  

Hence, the zeros of the quadratic equation are 3/2 and -1/3.

Now, for verification

Sum of zeros = – coefficient of x / coefficient of x2

3/2 + (-1/3) = – (-7) / 6 7/6 = 7/6  

Product of roots = constant / coefficient of x2

3/2 x (-1/3) = (-3) / 6 -1/2 = -1/2

Therefore, the relationship between zeros and their coefficients is verified.

2.Let f(x) = 3x2 ˗ x ˗ 4 = 0

3x2 ˗ 4x + 3x ˗ 4  = 0

⇒ x(3x ˗ 4) + 1 (3x ˗ 4)  = 0

⇒  (3x ˗ 4) (x + 1) = 0

To find the zeroes

(3x ˗ 4) = 0 or (x + 1) = 0

x = 4/3 or x=-1

So, the zeroes of f(x) are 4/3 and x=-1

Again, Sum of zeroes = 4/3 + (-1) = 1/3 = -b/a =

=(-Coefficient of x)/(Cofficient of x2)

Product of zeroes = 4/3  x (-1) = -4/3 = c/a=

= Constant term / Coefficient of x2

Therefore, the relationship between zeros

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above

javeir earned 56 dollors more than kyle so kyle and javier had 14w but javier made 56 dollors more so 14w plus 56 equals 70w so kyle has 14w

step-by-step explanation: hope i plz give me brainliest with the points so this is not constant cause it says last week so its clearly not every week