Can i get the answer quick

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p^3 - 7p^2q^2 + 2pq

Step-by-step explanation:

3pq +5p^2q^2 + p^3 = p^3 + 5p^2q^2 + 3pq

Let the number be x.

x + p^3 + 5p^2q^2 + 3pq + p^3 - pq

= 3p^3 - 2p^2q^2 + 4pq

x + p^3 + p^3 + 5p^2q^2 + 3pq - pq

= 3p^3 - 2p^2q^2 + 4pq

x + 2p^3 + 5p^2a^2 + 2pq

= 3p^3 - 2p^2q^2 + 4pq

x

= 3p^3 - 2p^2q^2 + 4pq - (2p^3 + 5p^2q^2 + 2pq)

= 3p^3 - 2p^2q^2 + 4pq - 2p^3 - 5p^2q^2 - 2pq

= 3p^3 - 2p^3 - 2p^2q^2 - 5p^2q^2 + 4pq - 2pq

= p^3 - 7p^2q^2 + 2pq

Therefore,

p^3 - 7p^2q^2 + 2pq should be added.

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