PLEASE HELP WILL MARK BRAINLIEST!

a. 125 degrees

b. 62 degrees

c. 58 degrees

d. 130 degrees

Step-by-step explanation:

I assume these are the inner angles of the polygons.

remember, for a polygon with n sides we can fully split it into n-2 triangles without overlap.

each of these triangles has an angle sum of 180 degrees.

to get the total inner angle sum of the polygon, we need to multiply 180 by (n-2) (= the number of triangles).

out of that total we can then calculate the size of the missing angle.

a. 6 sides, therefore 4 triangles

4×180 = 720 degrees

the missing angle is

angle = 720 - 88 - 152 - 125 - 105 - 125 = 125

b. 5 sides, 3 triangles

3×180 = 540 degrees

angle = 540 - 109 - 111 - 140 - 118 = 62

c. 4 sides, 2 triangles

2×180 = 360

angle = 360 - 60 - 142 - 100 = 58

d. 7 sides, 5 triangles

5×180 = 900

angle = 900 - 90 - 120 - 140 - 150 - 120 - 150 = 130

i can you with this question sweetie!

step-by-step explanation:

tell you what. i'll find the length of the medians and you can fill in the blanks where they belong.

br

b = (2a,0)

r = (a/2,b/2) remember these things are medians. they go to the 1/2 way point of the line opposite the vertex they face.

br^2 =   (2a - a/2)^2 + (0 - b/2)^2

br^2 = (3/2 a) ^2 + b^2 / 4

br^2 = 9/4 a^2 + b^2 / 4   we need to find some relationship between a and b.

let's try ab = bc  

ab = 2a

bc = (2a - a)^2 + (b - 0)^2

bc = sqrt(a^2 + b^2)

ab = bc

2a = sqrt(a^2 + b^2) square both sides.

4a^2 = a^2 + b^2 subtract a^2 from both sides.

sqrt(3a^2) = sqrt(b^2)

sqrt(3)a = b

let's put b into br^2

br^2 = 9/4 a^2 + 3b^2 / 4

br^2 = 12 a^2 / 4

br^2 = 3a^2 

br = sqrt(3) * a

cp

c = (a,b) ; p = (a,0) this is another application of the distance formula, and it is a good one.

cp^2 = (a - a)^2 + (b - 0)^2

cp^2 = 0 + b^2

cp^2 = b^2 which you can see from the diagram. 

cp = sqrt(b^2)

cp = b but b = sqrt(3) * a 

cp = sqrt(3)*a

aq

a = (0,0)

q = (3/2) a, b/2

aq^2 = (3a/2 -0)^2 + (b/2 - 0)^2

aq^2 = 9a^2/4 + b^2/4

but b = sqrt(3) * a 

aq^2 = 9a^2 / 4 + (sqrt(3)*a)^2 /4

aq^2 = 9 a^2/ 4 + 3 a^2 / 4

aq^2 = 12 a^2/4

aq^2 = 3 a^2

aq = (sqrt  3) * a which agrees with the other two.