To win the game, Elena has to roll an even number first and a number less than 3 second. Her probability of winning is StartFraction 6 over 36 EndFraction.

Sum of 6

Sum of 2 or 9

Sum (> 2 but < 5)

Step-by-step explanation:

We are given that :

Elena's probability of winning is 6 /36 = 1/6

And also that Martha's probability if winning is lower Than that of Elena ; Hence, Martha's outcome should be outcjnes whose probability is less than 1/6 (Elena's probability of winning)

Using a sample space that gives the sum of 2 dices.

Recall :

Probability = required outcome / Total possible outcomes

Total possible outcomes for a two dice throw = 6² = 36

Using the sample space attached, we can count the sums from the sample space :

To obtain a sum of 7 :

P(sum 7) = 6 /36 = 1/6

To obtain a sum of 6 :

P(sum 6) = 5 /36

Sum of 2 or 9:

P(sum of 2 or 9). = 5 / 36

Sum > 9 :

P(sum > 9). = 6/36

P Sum (> 2 but < 5) = 5 /36

Correct choices are probability values less than 6/36 which are :

Sum of 6

Sum of 2 or 9

Sum (> 2 but < 5)

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer