the sum of two positive consecutive integers is x. in terms of x, what is the value of the smaller of these two integers?​

In terms of x, the smaller integer is (x - 1)/2

Step-by-step explanation:

Two consecutive positive integers can be written as:

n and (n + 1)

Where n is an integer and:

n > 0.

notice that the smaller of the two integers is n.

We know that the sum of these two integers is equal to x, then:

n + (n + 1) = x

we can rewrite this as:

2n + 1 = x

solving this for n (the smaller of the two integers) we get:

2n = x - 1

n = (x - 1)/2

In terms of x, the smaller integer is (x - 1)/2

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer