If (p+2q)/p = 7/5 , find the value of q/p , where p ≠ 0​

Work Shown:

(p+2q)/p = 7/5

(p/p)+(2q/p) = 7/5

1 + 2(q/p) = 7/5

2(q/p) = 7/5 - 1

2(q/p) = 7/5 - 5/5

2(q/p) = (7-5)/5

2(q/p) = 2/5

q/p = (2/5)*(1/2)

q/p = (2*1)/(5*2)

q/p = 1/5

q/p = 1/5

Step-by-step explanation:

(p+2q)/p = 7/5

Multiply each side by p

(p+2q)/p *p = 7/5*p

(p+2q) = 7p/5

Multiply each side by 5

(p+2q)*5 = 7p/5 *5

5p + 10q = 7p

Subtract 5p from each side

5p + 10q -5p = 7p -5p

10 q = 2p

divide each side by p

10q/p = 2p/p

10 q/p = 2

Divide each side by 10

q/p = 2/10

q/p = 1/5

answer: the 4 kilogram bag

step-by-step explanation: this is because if you divide the number of kilograms into the total it will tell you how much each individual kilogram would be worth. 2 kilos is 7 and change 3 would be around 6 ish and the 4 kilo would be 4.6 and change and the 5 kilos would be like 4.88

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3