An object is dropped from 24 feet below the tip of the pinnacle atop a 1468-ft tall building. The height h of the object after t seconds is given by the equatior h= - 16t2 + 1444. Find how many seconds pass before the object reaches the ground. seconds pass before the object reaches the ground. (Type an integer or a decimal.)​

9.5 seconds pass before the object reaches the ground.

Step-by-step explanation:

Height of the ball:

The height of the ball after t seconds is given by the following equation:

Find how many seconds pass before the object reaches the ground.

This is t for which h(t) = 0. So

Since it is time, we only take the positive value.

9.5 seconds pass before the object reaches the ground.

4a. is 3 miles every hour

4b. is 1/3 of an hour per mile

step-by-step explanation:

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve