The distances in miles driven by a sample of nine different cars using 13 gallons of gasoline were 174, 201, 271, 208, 196, 340, 214, 236, and 385. Find the mean and the standard deviation for the distances traveled. How many cars fall within one standard deviation of the mean?

When You order the numbers you get

174 196 201 208 214  236 271 340 385

To get the mean, you add up all the numbers

Sum:2225

Then you divide it by how many test subjects there are (9 cars)

2225÷9=247.222222222 Which is your mean

Q1 is between 196 and 201

Q3 is between 271 and 340

If you get the mean of both, Q1 would be 198.5 and Q3 is 305.5

The amount of cars between them is 6

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation:

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.