Please help! Would be appreciated so much

25%.

Step-by-step explanation:

First, let's find the area of both circles. The area of a circle is given by:

The radius of the smaller circle is one. Thus, its area is:

The radius of the larger circle is two. Thus, its area is:

The probability that a random point chosen will be inside the small circle will be the area of the small circle over the total area. Hence:

The probability of a random point being in the small circle is 25%.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)