Given: ABC
Prove: The medians of ABC are concurrent.
What is step 10 in this proof?

As seen , what steps you have written  you just want to prove if in a triangle two medians have common point of intersection , a point P, then the third median will also pass through point P.

The point of intersection of medians is called Centroid.

The statement ahead of  :Statement: Point P lies on and .

Reason: from above algebra

Point P is the intersection of three medians which is  called Centroid of triangle.The Centroid divides the line from opposite vertex in the ratio of 2:1.

Step-by-step explanation:

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step-by-step explanation:

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step-by-step explanation:

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