Find the graph of the solution set of the following system of linear inequalities

the graph looks like this:-

Step-by-step explanation:

for inequality 1

if we take x = 0 we get y = -4

and if we take y =0 we get x = 16

so we get 2 points (0, -4) and (16, 0) and the graph must pass thru these two.

now checking if the origin satisfies the inequality or not

take x and y = 0

0 + 0 is not greater than or equal to -16

so origin doesn't satisfy the inequality.

shade the graph on the side, of the line, opposite to where the origin is.

for inequality 2

if we take x = 0 we get y = 2

and if we take y =0 we get x = -⅔

so we get 2 points (0, 2) and (-⅔, 0) and the graph must pass thru these two.

the line should be a dotted line.

now checking if the origin satisfies the inequality or not

take x and y = 0

0 + 0 is less than 2

so origin satisfies the inequality.

shade the graph on that side of the line where the origin is.

[ red line shows graph 1 whereas the blue dotted line represents graph ]

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

x = 12

y = 1

for the points!