A regular six sided die and an eight equal segment spinner, numbered 1 to 8, are rolled/spun simultaneously. What are the odds in favor of spinning a prime number on the spinner and rolling a number less or equal to 4 on the die?

1/3

Step-by-step explanation:

In statistics, the probability of both an event A and an event B happening is equal to the probability of A happening multiplied by the probability of event B happening.

Let's say spinning a prime number is event A and rolling a number ≤ 4 is event B.

There are 8 possibilities on an eight equal segment spinner, and there are 4 prime numbers between 1 and 8 (including 8), which are 2, 3, 5, and 7. This means that the probability of spinning a prime number is 4/8, or 1/2

There are 6 possibilities on a die, and there are 4 possibilities of rolling a 4 or less (1, 2, 3, 4). Therefore, the probability of rolling 4 or less on a die is 4/6, or 2/3

The probability of both of these happening can be calculated by multiplying these together, so 1/2 * 2/3 = 2/6 = 1/3

180

step-by-step explanation:

12-2=10

20-2=18

18x10=180

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step-by-step explanation:

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