Rewrite the equation 8x + 6x2 - 7= in standard form and identify a, b, and c. Select one:
a. a =5,b= 8.c = -7
b. a=6,6= 8,0 = 1
ca=5,b=8,0= 7
da= 8,b= 6.c = -7
40

a = 6

b = 8

c = -7

Step-by-step explanation:

In standard form, we have ;

y = ax^2 + bx + c

Here, we have;

6x^2 + 8x - 7

a is the coefficient of x^2 which is 6 in this case

b is the coefficient of x which is 8

c is the last number which is -7

So we have;

a = 6

b = 8

c = -7

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

step-by-step explanation: the answer is 27. first multiply .32 by 25 which equals 8. then add 8 to 25 which gives you 33. then you subtract that from 6 since she gave 6 to her brother.

,, add !