Nine children are to be divided into an A team, a B team and a C team of 3 each. The A team will play in one league, the B team in another, the C team in a third league. How many different divisions are possible

The answer is "840".

Step-by-step explanation:

Following are the number of ways in which selecting a team A  by 9 children:

Following are the number of ways in which selecting a team B  by remaining 6 children:

Following are the number of ways in which selecting a team C  by remaining 3 children:

Following are the number of ways in which making 3 teams by 9 children:

(Note: we've split by 3! Because it also is necessary to implement three teams between themselves)

Now 3 leagues have to be played. One is going to be run by each team.

That is the way it is

Different possible divisions

add 5 subtract 1

step-by-step explanation:

w'x is 0.

hope it