In the perfect square x^2+bx+c, why is the relationship between b and c C=(b/2)^2? Would the strategy work even if b is a negative? Also, would it work if b was an odd number? What would happen to c if b was odd?

me. I think you have to multiply so that you get the answer

Step-by-step explanation:

c = (b/2)² because b = 2c

If b is negative, then c = (-b/2)² , and x² - bx + c = (x-c)²

If b is an odd number, then c will be a fraction.

1: -2 3/4, -2 1/2, -14, 0, 3, 8 1/3

2: -4, -3, -2 1/2, -2 1/4, 3 1/4,

step-by-step explanation:

where are the images of the functions i can only see the question you typed.

step-by-step explanation: