The line 3y - x = 5 is the tangent to a circle at the point A(1,2). (1) Find the equation of yhe line passing through A and the centre of the circle. The equation of another line passing through the centre of the circle is x + 3y = 15. (2) Find the equation of the circle.​

i dont know

step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

y -5 = (-1/4)(x + 8)

step-by-step explanation:

44

step-by-step explanation:

the