Mathematics, 02.07.2021 19:40 Tooey2331
Find a so that the point (2,14) is on the graph of f(x)=ax^+2
Answers: 3
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X^2/100+y^2/25=1 the y-intercepts are at: a) (-10,0) and (10,0) b) (0,10) and (0,5) c) (0,-5) and (0,5)
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Find a so that the point (2,14) is on the graph of f(x)=ax^+2...
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