37. Two numbers are such that their difference, their sum and their
product are in the ratio 1:7: 24.
Find the product of the
number.

8 and 6

Step-by-step explanation:

Two numbers are such that their difference, their sum, and their product are to

each other as 1:7:24. Their product must equal what number?

:

Two numbers a & b

Let x = the multiplier

:

a - b = 1x

a + b = 7x

a * b = 24x

:

Add the 1st two equations

a - b = x

a + b = 7x

2a = 8x

a = 4x

or

x = .25a

:

a * b = 24x

Replace 24x; a = 4x therefore:

a * b = 6a

b = 6

;

Using the 1st equation

a - b = 1x

Replace b with 6 and x with .25a

a - 6 = .25a

a - .25a = 6

.75a = 6

a =

a = 8

:

Find the multiplier

a - b = x

8 - 6 = 2

:

Check this

a - b = 2 (1*2)

a + b = 14; (7*2)

a * b = 48: (24*2)

:

The numbers are 8 and 6; their products = 48

i got 142 as my answer

step-by-step explanation: