Which polynomial function has x-intercepts –1, 0, and 2 and passes through the point (1, –6)

y=3x(x+1)(x-2)=3x^3-3x^2-6x

Step-by-step explanation:

The polynomial function can be written in the form:

y=a(x-x1)(x-x2)(x-x3)

where

x1=-1

x2=0

x3=2

Therefore

y=a(x+1)(x-0)(x-2)=a(x^2+x)(x-2)=a(x^3-x^2-2x)

To find the value for "a" we use the info about the line passing in (1,-6):

-6=a(1-1-2)

a=3

y=3x(x+1)(x-2)=3x^3-3x^2-6x

the graph on the bottom right

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116