Im asking a question because yes +=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+ =+=+=+=+=+=+=+=+=+=+=+=+=+=+=+

ANSWER WITH A, B, C, OR D.

A fruit stand has to decide what to charge for their produce. They need $10 for 4 apples and 4 oranges. They also need $12 for 6 apples and 6 oranges. We put this information into a system of linear equations.

Can we find a unique price for an apple and an orange?

Choose 1

A

Yes; they should charge $1.00 for an apple and $1.50 for an orange.

B

Yes; they should charge $1.00 for an apple and $1.00 for an orange.

C

No; the system has many solutions.

D

No; the system has no solution.

I believe the answer would be A!

Step-by-step explanation:

If you need $10 total, then charging $1 for 4 apples would get you $4, and charging $1.50 for 4 oranges would get you $6, totaling $10!

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it