Suppose that Bag 1 contains a red (R), a blue (B) and a white (W) ball, while Bag 2 contains a red (R), a pink (P), a yellow (Y) and a green (G) ball. A game consists of you randomly drawing a ball from each of Bag 1 and Bag 2. (a) What are the 12 outcomes in the sample space S for this experiment? (b) You win the prize of baked goods if you draw at least 1 red ball. List the outcomes in the event that you win that prize, and use them to compute the probability of this event. You should assume that all outcomes in the sample spaces obtained in (a) are equally likely.

1 /2

Step-by-step explanation:

Given :

Bag 1 : Red (R) ; Blue (B) ; White (W)

Bag 2 : Red (R) ; Pink (P) ; Yellow (Y) ; Green (G)

Total number of possible outcomes :

3C1 * 4C1 = 3 * 4 = 12 outcomes

Sample space (S) ;

R B W

R RR RB RW

P PR PB PW

Y YR YB YW

G GR GB GW

To win price of baked goods ; Atleast one red ball must be drawn :

Probability of winning ; P(winning) = required outcome / Total possible outcomes

Required outcome = {RR, RB, RW, PR, YR, GR} = 6

Total possible outcomes = S = 12

P(winning) = 6/12 = 1/2

step-by-step explanation:

i'm pretty sure it would take 20 hours because it's half the men so you multiply the number of hours it takes by 2