A ball is thrown upward with an initial velocity (v) of 15 meters per second. Suppose that the initial height (h) above the ground is 7 meters. At what time will the ball hit the ground? The ball is on the ground when S = 0. Use the equation S = -52 + vt + h.
The ball will hit the ground in how many
seconds?

Step-by-step explanation:

Your equation is weird. The position equation for this situation is

and set it equal to 0 to solve for the time it takes to hit the ground. Those times come out to be

t = 3.47 sec and t = -.411 sec. But since time can never be negative, our time is 3.47 seconds

(What is that -52?)

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic