Solve the inequality and write the solution set using both set-builder notation and interval notation. -3a-15≤-2a+6

Set builder notation: {a | a ≥ -21}

Interval notation: [-21, ∞)

Step-by-step explanation:

A set represents a collection of things, objects, or numbers. A set builder notation is in the form y = {x | x is an odd number between 8 and 10}, which means y contains all the odd numbers between 8 and 10.

Interval notation is a way to define a set of numbers between a lower limit and an upper limit using end-point values. for example (8, 20) means numbers between 8 and 20.

Given -3a-15≤-2a+6; solving :

-3a - 15 ≤ -2a + 6

-3a + 2a ≤ 6 + 15

-a ≤ 21

dividing through by -1:

a ≥ -21

The solution is:

Set builder notation: {a | a ≥ -21}

Interval notation: [-21, ∞)

its the fourth option

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step-by-step explanation: