The following system of linear equations is homogeneous. {x+y+z2x−y+z=0=0

Group of answer choices

True

False

Is it possible for a homogeneous system of linear equations to have no solution?
Group of answer choices

Yes

No

d is correct

step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

10 you would take 50/ .2

step-by-step explanation:

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24