Choose the function that has: Domain: x*-1
Range: y# 2
O
Ax)= x+2
x-1
O
2x+1
Ax)=
x+1
2x+ 1
(x) =
x-1

Given:

To find:

The function for the given domain and range.

Solution:

A function is not defined for some values that makes the denominator equals to 0.

The denominator of functions in option A and C is .

So, the functions in option A and C are not defined for but defined for . Therefore, the options A and C are incorrect.

In option B, the denominator is equal to .

So, the function is not defined for . Thus, .

If degree of numerator and denominator are equal then the horizontal asymptote is , where a is the leading coefficient of numerator and b is the leading coefficient of denominator.

In option B, the leading coefficient of numerator is 2 and the leading coefficient of denominator is 1. So, the horizontal asymptote is:

It means, the value of the function cannot be 2 at any point. So, .

Hence, option B is correct.

450 is the final answer! : )

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x