The area of a square is increasing at a rate of 24 centimeters squared per second. Find the rate of change of the side of the square when it is 4 centimeters. The rate of change of the side is Number cm/sec.

3cm/s

Step-by-step explanation:

Area of a square is expressed as:

A = L²

Rate of change of area is expressed as:

dA/dt = dA/dL•dL/dt

Given that

dA/dt = 24cm²/s

L = 4cm

Required

dL/dt

Since dA/dl = 2L

dA/dl = 2(4)

dA/dl = 8cm

Subatitute the given values into the formula

24 = 8 dL/dt

dL/dt = 24/8

dL/dt = 3cm/s

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

i think its a and d

step-by-step explanation: