Mathematics, 30.06.2021 04:50 AIhunter2884

Cylinders A and B are similar. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

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Answer from: COOLIOMARIS

The question is incomplete. The complete question is :

Cylinders A and B are similar. The length of the cylinder A is 4 mm and the length of cylinder B is 6 mm. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

67.5 mm^3

Step-by-step explanation:

Given that :

Cylinder A and cylinder B are similar.

Let volume of cylinder A = 20 mm^3

We know the volume of a cylinder is given by V = $\pi r^2 h$

where, r is the radius of the cylinder

h is the height of the cylinder

We have to find the scale factor.

The length scale factor is = $\frac{6}{4}$

$=\frac{3}{2}$

Area scale factor $=\left(\frac{3}{2}\right)^2$

$=\frac{9}{4}$

∴ Volume scale factor $=\left(\frac{3}{2}\right)^3$

$=\frac{27}{8}$

Therefore, the volume of cylinder B is $=20 \times \frac{27}{8}$

= 67.5 mm^3

Cylinders A and B are similar. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B

Answer from: Quest

answer: okw

step-by-step explanation:

Answer from: Quest

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

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